ball is thrown horizontally at 7m/s from the top of a hill that 42m high. how far from the base of the cliff would the ball hit the ground

Answer 1

how long does it take to fall 42m? (s = 1/2 at^2)
horizontal speed is constant, so distance = speed * time

Answer 2

h = Vo*T+gT^2 = 42
0+9.8T^2 = 42
T = 2.07s. to hit gnd.
d = V*T = 7*2.07 = 14.49m.

Answer 3

Correction: h = Vo*T+0.5gT^2 = 42
0+4.9T^2 = 42
T = 2.93s.
d = V*T = 7*2.93 = 20.5m.