well, you know the conservation of momentum applies.
Take the ball B, the North momentum, so BAll A must have that same momentum in the S direction as there was no initial N-S component.
Then, take BAll B East momentum, subtract that from BallA initial East nomentum, so that is the BAll A East momentum.
Final total momentum then will equal initial momentum
Ball A with a mass of 0.500 kg is moving east at a velocity of 0.800 m/s. It strikes ball B, also of mass 0.500 kg, which is stationary. Ball A glances off B at an angle of 40.0° north of its original path. Ball B is pushed along a path perpendicular to the final path of ball A. What is the momentum (in kg m/s) of ball A after the collision?
2 answers
6.13
1 answer