To solve this problem, we need to examine the genotypes of the parents and determine the potential genotypes of their offspring.
Parental genotypes:
- Woman: XXbb (she is a female and has two X chromosomes, and is homozygous recessive for the baldness gene (bb))
- Man: XYBb (he is a male with one X chromosome and one Y chromosome, and is heterozygous for the baldness gene)
Possible gametes:
- The woman can only produce Xb gametes (since she is bb).
- The man can produce two types of gametes: XB (with the dominant baldness allele) and Y (which carries no baldness allele).
Possible offspring genotypes: When we combine the gametes from both parents, the possible combinations are:
- Xb from the mother and XB from the father: XBXb (bald)
- Xb from the mother and Y from the father: XYb (not bald)
Now, let's determine the phenotypes based on the offspring combinations:
- XBXb (bald) - This child will become bald because they inherit at least one dominant allele (B) from the father.
- XYb (not bald) - This child will not become bald because they have the genotype bb (with respect to baldness).
Now let's count the outcomes:
- 1 child with genotype XBXb (bald)
- 1 child with genotype XYb (not bald)
Total outcomes:
- Probability of child becoming bald = 1 out of 2 = 50%
- Probability of child not becoming bald = 1 out of 2 = 50%
Based on this analysis, the answer to the question is: d. There is a 50% chance that the child will become bald.