2 mol of water --> 2*18 g
1 mol O2 --2*16 g
(2*18/2*16) * 7.4 mg
= 9*7.4/8 = 8.325 mg
7400 grams O2 ---> 8325 grams H2O
---> 8325 mL H2O
or
8.325 liters
balanced equation =2 H(2)+ 1 O(2) -> 2H(2)O
A. What mass of H2O would be produced from7.4 mg of O2
B. What is the volume of H2O would be produced from 7.4kg of O2. Density of water = 1.000g/ml
1 answer