1. Write down the unbalanced equation:
Cl2 + NaOH → NaCl + NaClO2 + H2O
2. Balance the sodium atoms by putting a coefficient of 2 in front of NaOH:
Cl2 + 2NaOH → NaCl + NaClO2 + H2O
3. Balance the chlorine atoms by putting a coefficient of 3 in front of NaClO2:
Cl2 + 2NaOH → NaCl + 3NaClO2 + H2O
4. Balance the hydrogen atoms by putting a coefficient of 4 in front of H2O:
Cl2 + 2NaOH → NaCl + 3NaClO2 + 2H2O
5. The final balanced equation is:
Cl2 + 2NaOH → 2NaCl + 3NaClO2 + 2H2O
Balance this equation Cl2 + NaOH →NaCl + NaClO2 + H2O
Show all of the steps please in order
1 answer