Balance the redox equation. It occurs in acid solution.

Sn(s) + H+(aq) = Sn2+(aq) + H2(g)

I understand that first the equation needs to be put into halves.
Sn(s) = Sn2+(aq) and H+(aq) = H2(g)
Then,
Sn(s) = Sn2+(aq) + 2e- and ?
From here I am lost. Please help.

1 answer

Sn ==> Sn^2+ + 2e
2H^+ + 2e ==> H2
--------------------add 1 to 2.
Sn + 2H^+ + 2e ==> Sn^2+ + 2e + H2
Then cancel the two e on each side and you're left with the balanced equation.
Similar Questions
  1. Balancing redox reactionsBalance in acid solution 1. PH3+ I2 -> H3PO4 + I- 2. ClO3- + Cl- -> Cl2 Balance in basic solution Se ->
    1. answers icon 0 answers
    1. answers icon 6 answers
  2. I need help with balancing redox reactionsBalance in acid solution: 1) PH3+ I2 --> H3PO4+ I- 2) ClO3- + Cl- --> Cl2
    1. answers icon 0 answers
    1. answers icon 1 answer
more similar questions