Sn ==> Sn^2+ + 2e
2H^+ + 2e ==> H2
--------------------add 1 to 2.
Sn + 2H^+ + 2e ==> Sn^2+ + 2e + H2
Then cancel the two e on each side and you're left with the balanced equation.
Balance the redox equation. It occurs in acid solution.
Sn(s) + H+(aq) = Sn2+(aq) + H2(g)
I understand that first the equation needs to be put into halves.
Sn(s) = Sn2+(aq) and H+(aq) = H2(g)
Then,
Sn(s) = Sn2+(aq) + 2e- and ?
From here I am lost. Please help.
1 answer