To balance the given chemical equation \( \text{Ti}_3\text{N} + \text{MgO} \rightarrow \text{Mg}_3\text{N}_2 + \text{Ti}_2\text{O} \), we need to ensure that the number of each type of atom is the same on both sides of the equation.
Let's break it down step by step:
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Identify the elements and their quantities:
- Reactants: \( \text{Ti}_3\text{N} \) and \( \text{MgO} \)
- Products: \( \text{Mg}_3\text{N}_2 \) and \( \text{Ti}_2\text{O} \)
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Write down the unbalanced equation: \[ \text{Ti}_3\text{N} + \text{MgO} \rightarrow \text{Mg}_3\text{N}_2 + \text{Ti}_2\text{O} \]
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Count the atoms of each element:
- Left side:
- Ti: 3
- N: 1
- Mg: 1
- O: 1
- Right side:
- Ti: 2
- N: 2
- Mg: 3
- O: 1
- Left side:
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Start balancing:
- Balance nitrogen (N): To balance nitrogen, we have 1 on the left and 2 on the right. Thus, we need 2 \( \text{Ti}_3\text{N} \).
- Update the equation: \[ 2 \text{Ti}_3\text{N} + \text{MgO} \rightarrow \text{Mg}_3\text{N}_2 + \text{Ti}_2\text{O} \]
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Count the atoms again:
- Left side:
- Ti: 6
- N: 2
- Mg: 1
- O: 1
- Right side:
- Ti: 2
- N: 2
- Mg: 3
- O: 1
- Left side:
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Next, balance titanium (Ti): We have 6 Ti on the left and 2 on the right. We need 3 \( \text{Ti}_2\text{O} \) to achieve this.
- Update the equation: \[ 2 \text{Ti}_3\text{N} + \text{MgO} \rightarrow \text{Mg}_3\text{N}_2 + 3 \text{Ti}_2\text{O} \]
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Count the atoms again:
- Left side:
- Ti: 6
- N: 2
- Mg: 1
- O: 1
- Right side:
- Ti: 6
- N: 2
- Mg: 3
- O: 3
- Left side:
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Finally, balance magnesium (Mg): Now we have 1 Mg on the left and 3 Mg on the right, so we need 3 \( \text{MgO} \).
- The balanced equation becomes: \[ 2 \text{Ti}_3\text{N} + 3 \text{MgO} \rightarrow \text{Mg}_3\text{N}_2 + 3 \text{Ti}_2\text{O} \]
Now everything is balanced:
- Ti: 6 on each side
- N: 2 on each side
- Mg: 3 on each side
- O: 3 on each side
The balanced equation is: \[ 2 \text{Ti}_3\text{N} + 3 \text{MgO} \rightarrow \text{Mg}_3\text{N}_2 + 3 \text{Ti}_2\text{O} \]
So, the answers for the blanks are:
- Blank 1: 2
- Blank 2: 3
- Blank 3: 1 (for \( \text{Mg}_3\text{N}_2 \))
- Blank 4: 3
Final answer for the blanks:
- Blank 1: 2
- Blank 2: 3
- Blank 3: 1
- Blank 4: 3