To balance the chemical equation \( \text{Na}_2\text{O} + \text{CaBr}_2 \rightarrow \text{NaBr} + \text{CaO} \), we need to ensure that the number of atoms of each element is the same on both sides of the equation.
- Count the number of atoms for each element on both sides:
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Reactants:
- Na: 2 from \( \text{Na}_2\text{O} \)
- O: 1 from \( \text{Na}_2\text{O} \)
- Ca: 1 from \( \text{CaBr}_2 \)
- Br: 2 from \( \text{CaBr}_2 \)
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Products:
- Na: 1 from \( \text{NaBr} \)
- Br: 1 from \( \text{NaBr} \)
- Ca: 1 from \( \text{CaO} \)
- O: 1 from \( \text{CaO} \)
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Initially:
- Left: 2 Na, 1 O, 1 Ca, 2 Br
- Right: 1 Na, 1 O, 1 Ca, 1 Br
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Balance sodium (Na) and bromine (Br):
- To balance sodium and bromine, we can place a coefficient of 2 in front of \( \text{NaBr} \): \[ \text{Na}_2\text{O} + \text{CaBr}_2 \rightarrow 2 \text{NaBr} + \text{CaO} \]
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Recount the atoms:
After adding the coefficient:
- Left: 2 Na, 1 O, 1 Ca, 2 Br
- Right: 2 Na (from \( 2 \times \text{NaBr} \)), 1 O, 1 Ca, 2 Br
Now he equation is balanced.
Thus, the balanced equation is: \[ \text{Na}_2\text{O} + \text{CaBr}_2 \rightarrow 2 \text{NaBr} + \text{CaO} \]
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