Balance the following the chemical equation: _ Na2O + _ CaBr2 → _ NaBr + _ CaO

Answer 1

To balance the chemical equation \( \text{Na}_2\text{O} + \text{CaBr}_2 \rightarrow \text{NaBr} + \text{CaO} \), we will follow these steps:

1. Write down the number of each type of atom in the reactants and products.
2. Adjust coefficients to balance the atoms.

Starting with the unbalanced equation: \[ \text{Na}_2\text{O} + \text{CaBr}_2 \rightarrow \text{NaBr} + \text{CaO} \]

Count the number of atoms of each element:

• Reactants:

  • Na: 2 (from \(\text{Na}_2\text{O}\))
  • O: 1 (from \(\text{Na}_2\text{O}\))
  • Ca: 1 (from \(\text{CaBr}_2\))
  • Br: 2 (from \(\text{CaBr}_2\))

• Products:

  • Na: 1 (from \(\text{NaBr}\))
  • O: 1 (from \(\text{CaO}\))
  • Ca: 1 (from \(\text{CaO}\))
  • Br: 1 (from \(\text{NaBr}\))

Now, let's balance the equation:

To balance sodium (Na), we need 2 NaBr for every Na2O: \[ \text{Na}_2\text{O} + \text{CaBr}_2 \rightarrow 2 \text{NaBr} + \text{CaO} \]

Now recount:

• Reactants:

  • Na: 2
  • O: 1
  • Ca: 1
  • Br: 2

• Products:

  • Na: 2 (from \(2 \text{NaBr}\))
  • O: 1 (from \(\text{CaO}\))
  • Ca: 1 (from \(\text{CaO}\))
  • Br: 2 (from \(2 \text{NaBr}\))

Now all atoms are balanced.

The balanced equation is: \[ 1 \text{Na}_2\text{O} + 1 \text{CaBr}_2 \rightarrow 2 \text{NaBr} + 1 \text{CaO} \]

In terms of coefficients, it can be written as: \[ 1 \ Na_2O + 1 \ CaBr_2 \rightarrow 2 \ NaBr + 1 \ CaO \]

Thus, the final balanced equation is: \[ \text{Na}_2\text{O} + \text{CaBr}_2 \rightarrow 2 \text{NaBr} + \text{CaO} \]

Answer 2

Are you sure

Answer 3

Let's double-check the balancing of the equation step by step.

The unbalanced equation is:

\[ \text{Na}_2\text{O} + \text{CaBr}_2 \rightarrow \text{NaBr} + \text{CaO} \]

Step 1: Count the atoms on both sides

Reactants:

• Sodium (Na): 2 (from \(\text{Na}_2\text{O}\))
• Oxygen (O): 1 (from \(\text{Na}_2\text{O}\))
• Calcium (Ca): 1 (from \(\text{CaBr}_2\))
• Bromine (Br): 2 (from \(\text{CaBr}_2\))

Products:

• Sodium (Na): 1 (from \(\text{NaBr}\))
• Oxygen (O): 1 (from \(\text{CaO}\))
• Calcium (Ca): 1 (from \(\text{CaO}\))
• Bromine (Br): 1 (from \(\text{NaBr}\))

Step 2: Balance the equation

1. Balancing Sodium (Na):
   • We have 2 Na on the reactants' side, so we need 2 on the products' side. This means we should put a coefficient of 2 in front of NaBr:

\[ \text{Na}_2\text{O} + \text{CaBr}_2 \rightarrow 2 \text{NaBr} + \text{CaO} \]

2. Now recalculate the counts after the adjustment:

Reactants:

• Na: 2
• O: 1
• Ca: 1
• Br: 2

Products:

• Na: 2 (from \(2 \text{NaBr}\))
• O: 1 (from \(\text{CaO}\))
• Ca: 1 (from \(\text{CaO}\))
• Br: 2 (from \(2 \text{NaBr}\))

Now everything balances correctly:

• Sodium: 2 (reactants) = 2 (products)
• Oxygen: 1 (reactants) = 1 (products)
• Calcium: 1 (reactants) = 1 (products)
• Bromine: 2 (reactants) = 2 (products)

Final Balanced Equation: \[ \text{Na}_2\text{O} + \text{CaBr}_2 \rightarrow 2 \text{NaBr} + \text{CaO} \]

So, yes, this is the correct balanced equation! Thank you for prompting a review!