To balance the chemical equation \( \text{Na}_2\text{O} + \text{CaBr}_2 \rightarrow \text{NaBr} + \text{CaO} \), let's analyze the number of each type of atom on both sides of the equation.
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Count the atoms on the left side:
- Na: 2 from \( \text{Na}_2\text{O} \)
- Ca: 1 from \( \text{CaBr}_2 \)
- Br: 2 from \( \text{CaBr}_2 \)
- O: 1 from \( \text{Na}_2\text{O} \)
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Count the atoms on the right side:
- Na: 1 from \( \text{NaBr} \)
- Ca: 1 from \( \text{CaO} \)
- Br: 1 from \( \text{NaBr} \)
- O: 1 from \( \text{CaO} \)
Now, we start the balancing process:
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We have:
- Sodium (Na): 2 on the left, 1 on the right.
- Calcium (Ca): 1 on both sides.
- Bromine (Br): 2 on the left, 1 on the right.
- Oxygen (O): 1 on both sides.
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Place a coefficient of 2 in front of \( \text{NaBr} \) on the right side to balance Na and Br: \[ \text{Na}_2\text{O} + \text{CaBr}_2 \rightarrow 2 \text{NaBr} + \text{CaO} \]
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Now recount the atoms:
- Left:
- Na: 2
- Ca: 1
- Br: 2
- O: 1
- Right:
- Na: 2 (from \( 2 \text{NaBr} \))
- Ca: 1
- Br: 2 (from \( 2 \text{NaBr} \))
- O: 1
- Left:
Now both sides have equal amounts of each atom. Thus, the balanced equation is:
\[ \text{Na}_2\text{O} + \text{CaBr}_2 \rightarrow 2 \text{NaBr} + \text{CaO} \]
The coefficients to balance the equation are:
- Na2O: 1
- CaBr2: 1
- NaBr: 2
- CaO: 1
This corresponds to the ratio of 1:1:2:1.
The correct answer is c (1:1:2:1).
2 answers