Balance the following the chemical equation:

Question

___ MgO + ____ CaS → _____ MgS + ____ CaO

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Answer 1

To balance the chemical equation \( ___ \text{MgO} + ___ \text{CaS} \rightarrow ___ \text{MgS} + ___ \text{CaO} \), we need to ensure that the number of atoms of each element on the reactant side matches those on the product side.

1. List the compounds:

   • Reactants: MgO, CaS
   • Products: MgS, CaO

2. Count the atoms of each element:

   • Reactants:

     • Mg: 1 (from MgO)
     • O: 1 (from MgO)
     • Ca: 1 (from CaS)
     • S: 1 (from CaS)

   • Products:

     • Mg: 1 (from MgS)
     • S: 1 (from MgS)
     • Ca: 1 (from CaO)
     • O: 1 (from CaO)

3. Since each side has one of each atom, we can conclude that the equation is already balanced.

4. The balanced equation is: \[ 1 \text{MgO} + 1 \text{CaS} \rightarrow 1 \text{MgS} + 1 \text{CaO} \]

Therefore, the blanks to fill in are:

• Blank 1: 1
• Blank 2: 1
• Blank 3: 1
• Blank 4: 1

Final answer:

• Blank 1: 1
• Blank 2: 1
• Blank 3: 1
• Blank 4: 1

Answer 2

Balance the following the chemical equation:

___ N2 +____ O2 → ____ NO

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Answer 3

To balance the chemical equation

\[ ___ \text{N}_2 + ___ \text{O}_2 \rightarrow ___ \text{NO} \]

we follow these steps:

1. List the reactants and products:

   • Reactants: \( \text{N}_2 \), \( \text{O}_2 \)
   • Product: \( \text{NO} \)

2. Count the initial atoms for each element:

   • In \( \text{N}_2 \):
     • N: 2
     • O: 0
   • In \( \text{O}_2 \):
     • N: 0
     • O: 2
   • In \( \text{NO} \):
     • N: 1
     • O: 1

3. Balance the nitrogen (N) atoms first:

   • We need 2 N atoms on the right (since there are 2 in \( \text{N}_2 \)), so we place a coefficient of 2 in front of \( \text{NO} \): \[ \text{N}_2 + \text{O}_2 \rightarrow 2 \text{NO} \]

4. The nitrogen atoms are now balanced (2 N on each side). Now, balance the oxygen (O) atoms:

   • We now have 2 O atoms on the right (from \( 2 \text{NO} \)).
   • Since each \( \text{O}_2 \) molecule provides 2 O atoms, we can balance that with a coefficient of 1: \[ \text{N}_2 + 1 \text{O}_2 \rightarrow 2 \text{NO} \]

5. Now we have:

   • Reactants: \( 1 \text{N}_2 \) and \( 1 \text{O}_2 \) (which gives 2 O atoms)
   • Products: \( 2 \text{NO} \) (which gives 2 N atoms and 2 O atoms)

The balanced equation is:

\[ 1 \text{N}_2 + 1 \text{O}_2 \rightarrow 2 \text{NO} \]

Finally, the answers for the blanks are:

• Blank 1: 1
• Blank 2: 1
• Blank 3: 2

Answer 4

Balance the following the chemical equation:

____ Ti3N + _____ MgO → ______ Mg3N2 + _____ Ti2O

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Answer 5

To balance the chemical equation

\[ ___ \text{Ti}_3\text{N} + ___ \text{MgO} \rightarrow ___ \text{Mg}_3\text{N}_2 + ___ \text{Ti}_2\text{O} \]

we need to follow these steps:

1. List the compounds:

   • Reactants: Ti₃N, MgO
   • Products: Mg₃N₂, Ti₂O

2. Count the atoms of each element in the unbalanced equation:

   • In Ti₃N:
     • Ti: 3
     • N: 1
   • In MgO:
     • Mg: 1
     • O: 1
   • In Mg₃N₂:
     • Mg: 3
     • N: 2
   • In Ti₂O:
     • Ti: 2
     • O: 1

3. Balance the nitrogen (N) atoms first:

   • We have 1 N atom from Ti₃N and 2 N atoms from Mg₃N₂. To balance the N, we need 2 Ti₃N: \[ 2 \text{Ti}_3\text{N} + ___ \text{MgO} \rightarrow 1 \text{Mg}_3\text{N}_2 + ___ \text{Ti}_2\text{O} \]
   • This gives us 2 N from the 2 Ti₃N on the left side.

4. Now balance the titanium (Ti) atoms:

   • From 2 Ti₃N, we have 6 Ti atoms (2 × 3 = 6).
   • To balance the Ti on the product side, we need 3 Ti₂O (since each has 2 Ti): \[ 2 \text{Ti}_3\text{N} + ___ \text{MgO} \rightarrow 1 \text{Mg}_3\text{N}_2 + 3 \text{Ti}_2\text{O} \]

5. Now balance the magnesium (Mg) atoms:

   • We have 3 Mg atoms needed on the right side from Mg₃N₂, so we need 3 MgO on the left: \[ 2 \text{Ti}_3\text{N} + 3 \text{MgO} \rightarrow 1 \text{Mg}_3\text{N}_2 + 3 \text{Ti}_2\text{O} \]

6. Now let's check the complete balance:

   • Left side:

     • Ti: 2 × 3 = 6
     • N: 2 × 1 = 2
     • Mg: 3 × 1 = 3
     • O: 3 × 1 = 3

   • Right side:

     • Ti: 3 × 2 = 6
     • N: 1 × 2 = 2
     • Mg: 3 × 1 = 3
     • O: 3 × 1 = 3

Both sides are balanced!

The balanced equation is:

\[ 2 \text{Ti}_3\text{N} + 3 \text{MgO} \rightarrow 1 \text{Mg}_3\text{N}_2 + 3 \text{Ti}_2\text{O} \]

So, the answers for the blanks are:

• Blank 1: 2
• Blank 2: 3
• Blank 3: 1
• Blank 4: 3

Answer 6

Which situation would react faster and why?



a
Example A would be faster because of a low surface area.
b
Example B would be faster because of a low surface area.
c
Example B would be faster because of a high surface area.
d
Example A would be faster because of a high surface area.

Answer 7

To determine which example would react faster based on surface area, we need to understand that a higher surface area typically leads to a faster reaction rate. This is because a larger surface area allows more reactant particles to collide with each other, increasing the frequency of collisions that lead to chemical reactions.

Given the options provided:

• a. Example A would be faster because of a low surface area.
  This statement is incorrect; lower surface area usually results in slower reaction rates.

• b. Example B would be faster because of a low surface area.
  This statement is also incorrect for the same reason as above.

• c. Example B would be faster because of a high surface area.
  This statement is correct if Example B indeed has a higher surface area, making it reactive faster.

• d. Example A would be faster because of a high surface area.
  This statement would be correct only if Example A has the high surface area, but it contradicts option a.

Without knowing the specific details of Examples A and B, if Example B has a higher surface area than Example A, the correct response would be c. Example B would be faster because of a high surface area.

Please let me know if you have further details about Examples A and B, and I can provide a more precise answer!

Answer 8

Match the following terms to the correct definitions

Column A
1.
products:
2.
reactants:

3.
covalent bond:
4.
electronegativity:
5.
ionic bond:
6.
polar covalent bond:
7.
valence electrons:

Column B
a.the substances after a chemical reaction occurs
b.a force that holds atoms together by sharing electrons
c.a force that holds atoms together by unequally shared electrons
d.a value that describes the relative strength with which an atom of an element attracts electrons to itself in a chemical bond.
e.the electrons in the outermost orbitals of an atom
f.the substances before a chemical reaction occurs
g.a force that holds oppoitely charged atoms (or groups of atoms) together

Answer 9

Below are the correct matches between the terms in Column A and their corresponding definitions in Column B:

Column A

1. products:
   Match: a. the substances after a chemical reaction occurs

2. reactants:
   Match: f. the substances before a chemical reaction occurs

3. covalent bond:
   Match: b. a force that holds atoms together by sharing electrons

4. electronegativity:
   Match: d. a value that describes the relative strength with which an atom of an element attracts electrons to itself in a chemical bond

5. ionic bond:
   Match: g. a force that holds oppositely charged atoms (or groups of atoms) together

6. polar covalent bond:
   Match: c. a force that holds atoms together by unequally shared electrons

7. valence electrons:
   Match: e. the electrons in the outermost orbitals of an atom

Summary of Matches

1 - a
2 - f
3 - b
4 - d
5 - g
6 - c
7 - e