To balance the chemical equation \( \text{Cu} + \text{HgNO}_3 \rightarrow \text{Cu(NO}_3)_2 + \text{Hg} \), we can follow these steps:
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List the number of atoms for each element on both sides of the equation:
- Left side:
- Cu: 1
- Hg: 1
- N: 1
- O: 3
- Right side:
- Cu: 1
- Hg: 1
- N: 2 (from Cu(NO₃)₂)
- O: 6 (from Cu(NO₃)₂)
- Left side:
-
Start balancing the equation:
- We have 2 nitrogen (N) atoms and 6 oxygen (O) atoms on the right side from \( \text{Cu(NO}_3)_2 \). This means we need to adjust the coefficient in front of \( \text{HgNO}_3 \) to supply the necessary 2 nitrogen atoms and 6 oxygen atoms.
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Set the coefficient in front of \( \text{HgNO}_3 \):
- If we place a coefficient of 2 in front of \( \text{HgNO}_3 \), we will have:
- 2 HgNO₃ provides 2 nitrogen and 6 oxygen.
- The balanced equation will look like this: \[ \text{Cu} + 2\text{HgNO}_3 \rightarrow \text{Cu(NO}_3)_2 + 2\text{Hg} \]
- If we place a coefficient of 2 in front of \( \text{HgNO}_3 \), we will have:
-
Re-count the atoms:
- Now we have:
- Left side:
- Cu: 1
- Hg: 2
- N: 2
- O: 6
- Right side:
- Cu: 1
- Hg: 2
- N: 2
- O: 6
- Left side:
- Now we have:
The equation is balanced. Therefore, the coefficient that should go in front of \( \text{HgNO}_3 \) is 2.