balance the following chemical reaction:

Question

fe(s) + o3(g) = fe2o3(s) + co2(g)

Answer 1

i meant: fe(s) + o3(g) = fe2o3(s) + o2(g)

also i thought it would be: 2fe + 2o3 = fe2o3 + o2
but that leaves an extra oxygen.

Answer 2

actually i think i figured it out =

2fe + 4o3 = fe2o3 + 3o2

is that correct?

Answer 3

Your equation is not balanced, since you have an even number of O on the left, and an odd number on the right. Also, you need to use proper capitalization, such as Fe, CO2, O2

Also, you have CO2 on the right, but no C on the left.
I suspect you have garbled things.

Answer 4

I agree with oobleck that something is garbled.
Frankly, I doubt that oxygen is produced although it might be possible. Reacting with O3 should oxidize Fe as is to Fe2O3 and this equation would do it. 2Fe(s) + O3(g) ==> Fe2O3(s). There is no need for O2 to be produced. If that were the case you would form Fe2O3 and any EXCESS O3 would be a second equation of 2O3(g) ==> 3O2(g).You CAN balance the other one though this way.
2Fe + 3O3 ==> Fe2O3 + 3O2.

Answer 5

Fe + O2 → Fe2O3 is the unbalanced form of chemical reaction.

Balancing the simple molecules first, in this case the O2

Fe + 3O2→ Fe2O3 there are now 6 O atoms on the left, there must also be 6 O atoms on the right.

Fe + 3O2 → 2Fe2O3

Balance the rest of the equation.

4Fe + 3O2→ 2Fe2O3