Balance the following chemical equation ___Ti3N+___MgO—>___Mg3N2+___Ti2O

Answer 1

To balance the chemical equation \( \text{Ti}_3\text{N} + \text{MgO} \rightarrow \text{Mg}_3\text{N}_2 + \text{Ti}_2\text{O} \), follow these steps:

1. Write down the unbalanced equation: \[ \text{Ti}_3\text{N} + \text{MgO} \rightarrow \text{Mg}_3\text{N}_2 + \text{Ti}_2\text{O} \]

2. Count the number of each type of atom on both sides:

   • Reactants:
     • Ti: 3
     • N: 1
     • Mg: 1
     • O: 1
   • Products:
     • Ti: 2
     • N: 2
     • Mg: 3
     • O: 1

3. Start balancing the most complex compound or the element that appears in the smallest quantity:

   • Start with nitrogen (N). There is 1 N on the left and 2 N on the right. Therefore, place a coefficient of 2 in front of \(\text{Ti}_3\text{N}\) on the left: \[ 2 \text{Ti}_3\text{N} + \text{MgO} \rightarrow \text{Mg}_3\text{N}_2 + \text{Ti}_2\text{O} \]

4. Update atom counts:

   • Reactants:
     • Ti: 6 (from \(2 \times \text{Ti}_3\text{N}\))
     • N: 2 (from \(2 \times \text{Ti}_3\text{N}\))
     • Mg: 1
     • O: 1
   • Products:
     • Ti: 2
     • N: 2
     • Mg: 3
     • O: 1

5. Now balance titanium (Ti): There are 6 Ti on the left and 2 Ti on the right. Place a coefficient of 3 in front of \(\text{Ti}_2\text{O}\): \[ 2 \text{Ti}_3\text{N} + \text{MgO} \rightarrow \text{Mg}_3\text{N}_2 + 3 \text{Ti}_2\text{O} \]

6. Update atom counts:

   • Reactants:
     • Ti: 6
     • N: 2
     • Mg: 1
     • O: 1
   • Products:
     • Ti: 6 (from \(3 \times \text{Ti}_2\text{O}\))
     • N: 2
     • Mg: 3
     • O: 3 (from \(3 \times \text{Ti}_2\text{O}\))

7. Finally, balance magnesium (Mg): There are 3 Mg on the right, so place a coefficient of 3 in front of \(\text{MgO}\): \[ 2 \text{Ti}_3\text{N} + 3 \text{MgO} \rightarrow \text{Mg}_3\text{N}_2 + 3 \text{Ti}_2\text{O} \]

8. Final check of atom counts:

   • Reactants:
     • Ti: 6
     • N: 2
     • Mg: 3
     • O: 3
   • Products:
     • Ti: 6
     • N: 2
     • Mg: 3
     • O: 3

Since both sides are balanced, the final balanced equation is: \[ \boxed{2 \text{Ti}_3\text{N} + 3 \text{MgO} \rightarrow \text{Mg}_3\text{N}_2 + 3 \text{Ti}_2\text{O}} \]