To balance the chemical equation \(2Ag_2O \rightarrow \) , we need to determine the products. The decomposition of silver oxide yields silver and oxygen:
- Decomposition reaction: \[ 2Ag_2O \rightarrow 4Ag + O_2 \]
So the correctly balanced equation is:
- Ag: 4
- O: 2
Now we fill in the responses:
- Response area Ag: 4
- Response area O2: 1 (since we have one molecule of oxygen gas)
For the second part, to support the argument that the chemical equation violates the law of conservation of matter:
- Statement completion: "There are more hydrogen atoms on the right side of the arrow than on the left side."
Lastly, to balance the equation \(4NaCl + 2SO_2 + 4H_2O + O_2 \rightarrow Na_2SO_4 + 4HCl\):
Let's evaluate how to balance each element:
-
Sodium (Na): 4 on the left side (from \(4NaCl\)), and 2 on the right side (from \(Na_2SO_4\)), indicating we need 2 Na_2SO_4 to balance Na.
-
Chlorine (Cl): 4 from \(4HCl\) which goes with the \(4NaCl\).
-
Sulfur (S): 2 from \(2SO_2\) need to match \(2Na_2SO_4\) which contains 2 sulfur atoms.
-
Oxygen (O): Needs to be calculated, we have 2 × 2 (from \(2SO_2\)) + 4 (from \(4H_2O\)) + 1x (from O2) = 4 + 4 + 2 + x = 10 (let’s balance with 6 from \(O_2\) to make 10). We find we need to add enough O2.
After all balancing, the correctly balanced coefficients should be 1 for \(Na_2SO_4\) and 4 for \(HCl\).
- Select the numbers:
- Choose: 1
- Choose: 4
Thus, the balanced equation with them should be:
- \(4NaCl + 2SO_2 + 4H_2O + 1O_2 \rightarrow 2Na_2SO_4 + 4HCl\).
If you have any additional questions or need further assistance, feel free to ask!