To balance the equation 4Ag2O → Ag + O2, first we will analyze the reactants and products.
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In 4Ag2O, we have:
- 4 moles of Ag2O which gives us:
- 8 Ag atoms (because each Ag2O contains 2 Ag)
- 4 O atoms (because each Ag2O contains 1 O)
- 4 moles of Ag2O which gives us:
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In the products, we have:
- Each O2 contains 2 O atoms, so to balance with 4 O atoms from the reactants, we need 2 O2 molecules.
Therefore, the balanced products would be 8 Ag and 2 O2.
The balanced equation will look like this:
4Ag2O → 8Ag + 2O2
You can drag the responses to the correct areas:
- Drag "Ag" to the response area for the silver atom on the right side.
- Drag "O2" to the response area for the oxygen on the right side.
So the final answer will be:
4Ag2O → 8Ag + 2O2