Balance the equation:
Note: If a chemical species coefficient is "1" then "1" needs to be entered in the field before that species.
__MnO4(–) + __H(+) + __C2O4(2–) __Mn(2+) + __H2O + __CO2
i need a check pls
4 answers
on this one i got:2,16,2,2,8,4 but it say that the second(2)which is the coefficent for C204(2-) and the 4 on the co2 is wrong ? what might be the problem?
need the check pls
Mn goes from +7 on the left to +2 on the right. C goes from +6 on the left (for both C atoms) to +8 on the right (for 2 C atoms). [Place a 2 in front of CO2 to start]. To make the electron loss and gain equal, multiply the Mn half reaction by 2 and the C2O4/2CO2 half reaction by 5 (10 e gained=10 e lost)
Of course the 2 and 5 coefficients balance only the redox part of the equation. You must still balance the H^+ and H2O by inspection.