Since there are a total of 18 pecans, and a total of 54 nuts in the bag (18 pecans + 18 walnuts + 18 almonds), the probability of NOT randomly selecting a pecan would be:
(54 - 18) / 54 = 36 / 54 = 2 / 3 = 0.6667 or 66.67%
bag of mixed nuts contains 18 pecans, 18 walnuts, and 18 almonds. What is the probability of NOT randomly selecting a pecan from the bag?
2 answers
as fraction please
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