d = 10 hours
C = 10 000 bacteria
N(t) = 10 000(2)^(t/10) is your equation
Bacteria have a doubling time of roughly 10 hours. A normal bacteria starting population would be approximately 10,000 bacteria per ml of fluid...I am not sure if I have done these questions correctly and would like some confirmation before I hand this in to be marked!
a.) Write an equation to model this exponential growth, with B(t) representing the number of bacteria per m; and t representing the time in hours.
I did this B=10,000(2^10)^n
I am not sure that this is correct?!
4 answers
yes, sure... what are these variables? d C and then N, I have never heard of this before? Can you please clarify just a tad? Thanks and much appreciation to you!
Looking at this again, I am sure that mine is right. Mine is the same as yours. The only difference is the variables, and I also didn't type out the last part of my solution where the 10 hours is placed over t...I was taught to use n where you use t. I am using B(t) because I was told to, in the question and in my notes. As for N(t) again I think it is just a variable thing. So thanks for confirming my answer! Much appreciation to you!
No, your equation is not correct you do need the n/10 the way anonomous had it for you.
Just test it with values, eg time = 10
Your equation would result in B = 10000(2^20) which would be ridiculous
the equation that anonymous has would give
N(10) = 10000(2^1) = 20000, the right answer
Your exponent variable has to be divided by the doubling period, which in this case is 10 hours
Just test it with values, eg time = 10
Your equation would result in B = 10000(2^20) which would be ridiculous
the equation that anonymous has would give
N(10) = 10000(2^1) = 20000, the right answer
Your exponent variable has to be divided by the doubling period, which in this case is 10 hours
1 answer