Question 1
1. What is the mass of each reactant?
- Magnesium: (Please provide specific values if available, otherwise we can explore a hypothetical value)
- Oxygen: (Please provide specific values if available, otherwise we can explore a hypothetical value)
2. The total mass of all the reactants is:
- Total mass of reactants = Mass of Magnesium + Mass of Oxygen
3. The total mass of the products is:
- Total mass of products = Mass of Magnesium Oxide produced (please provide this value if available)
Question 2
4. Does this experimental data support the Law of Conservation of Mass? Explain in full sentences.
Yes, the experimental data supports the Law of Conservation of Mass, which states that mass cannot be created or destroyed in a chemical reaction. In the experiments, if the total mass of the reactants equals the total mass of the products, it confirms that the mass is conserved. For example, if we add the mass of magnesium and oxygen before the reaction and find that it is equal to the mass of magnesium oxide after the reaction, this agreement indicates that no mass has been lost or gained in the process.
Question 3
5. Based on the Law of Conservation of Mass, calculate the amount of magnesium that will react with all 15.0 grams of oxygen to produce 39.5 grams of magnesium oxide.
- To find the amount of magnesium that reacts, use the equation: \[ \text{mass of magnesium} + \text{mass of oxygen} = \text{mass of magnesium oxide} \] Rearranging gives: \[ \text{mass of magnesium} = \text{mass of magnesium oxide} - \text{mass of oxygen} \] \[ \text{mass of magnesium} = 39.5 , \text{grams} - 15.0 , \text{grams} = 24.5 , \text{grams} \]
Question 4
6. Assuming the magnesium and oxygen will react completely with one another, predict the mass of magnesium oxide that will be produced.
If all of the magnesium and oxygen react completely, the total mass of magnesium oxide produced can be calculated as follows: \[ \text{mass of magnesium oxide} = \text{mass of magnesium} + \text{mass of oxygen} \] (Please provide the actual mass values for magnesium and oxygen to compute this prediction.)
Question 5
7. Predict the mass of oxygen that will be left over after the reaction of 45.7 g of magnesium and 55.2 g of oxygen.
To predict the mass of leftover oxygen, follow these steps:
- Calculate the total mass of the reactants (45.7 g Mg + 55.2 g O).
- Determine the mass of magnesium oxide produced using the stoichiometry of the balanced chemical equation.
- The mass of leftover oxygen would be the initial mass of oxygen minus the mass that reacted.
Let’s say the reaction produces 100 grams of magnesium oxide: \[ \text{mass of leftover oxygen} = \text{initial oxygen} - \text{mass of reacted oxygen} \] (Hypothetical calculations would need the actual amount of oxygen that reacted.)
Question 6
8. Explain why the measured masses above violate the Law of Conservation of Mass. Use specific language and evidence from the reaction to support your answer.
If the measured masses of the reactants and products do not conform to the Law of Conservation of Mass, it suggests an error in the experiment. For instance, if the total mass of the products is less than the mass of the reactants, this could mean that some of the product escaped as gas, or that the reaction was not contained properly, leading to mass loss. Alternatively, if the products weigh more than the reactants, this would suggest the addition of mass from an external source which contradicts the law. Such an occurrence would indicate a need to reassess the experimental setup and ensure that all materials are accounted for. The evidence lies within the precise measurements of reactants and products, which should equivalently demonstrate that the two sides of the reaction equation are balanced.