3Ba(NO3)2(aq) + 2Na3PO4(aq) ==> Ba3(PO4)2 + 6NaNO3
3Ba^2+(aq) + 6[NO3]^-(aq) + 6Na^+(aq) + 2[PO4]^3-(aq)==> Ba3(PO4)2(s) + 6Na^+(aq) + 6[NO3]^-(aq)
1 is the balanced molecular equation.
2 is the total ionic equation.
3. To find the net ionic equation, use equation 2 and cancel ions that appear on both sides of the equation. What is left is the NET ionic equation.
Confirm that I didn't miss a sign or that I didn't make a typo.
Ba(NO3)2(aq) Na3PO4(aq)
need to find Molecular, ionic and net ionic Equation
1 answer