Asked by pickles
B
6
5
4
A
3
C
2
D
1
4
-3
-2
-1
0
1
2
3
4
5
6
7
8
-1
Suppose the paralleolgram on the coordinate plane is dilated in reference to the origin using a magnitude of 3. What would the coordinates be of the new vertex A'?
(1 point)
A′=
(
,
)
6
5
4
A
3
C
2
D
1
4
-3
-2
-1
0
1
2
3
4
5
6
7
8
-1
Suppose the paralleolgram on the coordinate plane is dilated in reference to the origin using a magnitude of 3. What would the coordinates be of the new vertex A'?
(1 point)
A′=
(
,
)
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the coordinates of the new vertex \( A' \) after dilating the point \( A \) in reference to the origin with a magnitude of \( 3 \), we need the original coordinates of point \( A \).
Assuming the given points represent distances along the axes, let's summarize the coordinates:
- Point \( A \) is given as \( (0, 1) \).
To dilate a point \( (x, y) \) by a factor of \( k \), the new coordinates \( (x', y') \) are calculated as:
\[
x' = k \cdot x
\]
\[
y' = k \cdot y
\]
Given \( k = 3 \) and the coordinates of point \( A \) as \( (0, 1) \):
\[
x' = 3 \cdot 0 = 0
\]
\[
y' = 3 \cdot 1 = 3
\]
Thus, the coordinates of the new vertex \( A' \) would be:
\[
A' = (0, 3)
\]
So, the final answer is:
\[
A' = (0, 3)
\]
Assuming the given points represent distances along the axes, let's summarize the coordinates:
- Point \( A \) is given as \( (0, 1) \).
To dilate a point \( (x, y) \) by a factor of \( k \), the new coordinates \( (x', y') \) are calculated as:
\[
x' = k \cdot x
\]
\[
y' = k \cdot y
\]
Given \( k = 3 \) and the coordinates of point \( A \) as \( (0, 1) \):
\[
x' = 3 \cdot 0 = 0
\]
\[
y' = 3 \cdot 1 = 3
\]
Thus, the coordinates of the new vertex \( A' \) would be:
\[
A' = (0, 3)
\]
So, the final answer is:
\[
A' = (0, 3)
\]
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