axis of symmetry of f(x)=2x^(2)+4x+3

Answer 1

The axis of symmetry of a parabola with equation f(x) = ax^2 + bx + c is given by the formula x = -b/(2a).

In this case, the equation is f(x) = 2x^2 + 4x + 3. Therefore, a = 2 and b = 4.

The axis of symmetry is x = -4/(2*2) = -4/4 = -1.

So, the axis of symmetry of the function f(x) = 2x^2 + 4x + 3 is x = -1.