Let's assume the cost of an average movie ticket in the United States is x dollars.
Using this assumption, we can set up two equations to represent the given information:
3y + 2z = 78.63
3z + 2y = 74.32
where y represents the cost of an average movie ticket in Japan and z represents the cost of an average movie ticket in Switzerland.
Simplifying the equations, we get:
3y + 2z = 78.63
2y + 3z = 74.32
We can solve for y in the first equation:
3y + 2z = 78.63
3y = 78.63 - 2z
y = (78.63 - 2z)/3
We can then substitute this expression for y into the second equation:
2((78.63 - 2z)/3) + 3z = 74.32
52.42 - (4/3)z + 3z = 74.32
(5/3)z = 21.9
z = 13.14
Substituting this value back into the expression for y:
y = (78.63 - 2(13.14))/3 = 17.45
Therefore, the average movie ticket prices in Japan, Switzerland, and the United States are approximately $17.45, $13.14, and x, respectively.
Average movie prices in the United States are, in general, lower than in other countries. It would cost $78.63 to buy three tickets in Japan plus two tickets in Switzerland. Three tickets in Switzerland plus two tickets in Japan would cost $74.32. How much does qn average movie ticket cost in each of these countries.
5 answers
Gabe Amodeo, a nuclear physicist, needs 80 liters of a 30% acid solution
To make 80 liters of a 30% acid solution, you would need:
- 24 liters of pure acid (since 30% of 80 is 24)
- 56 liters of a neutral solution to mix with the pure acid to make a total of 80 liters
So you would mix 24 liters of acid with 56 liters of neutral solution to make 80 liters of a 30% acid solution.
- 24 liters of pure acid (since 30% of 80 is 24)
- 56 liters of a neutral solution to mix with the pure acid to make a total of 80 liters
So you would mix 24 liters of acid with 56 liters of neutral solution to make 80 liters of a 30% acid solution.
Gabe Amodeo, a nuclear physicist, needs 80 liters of a 30% acid solution. He currently has a 20% solution and a 60% solution. How many liters of each does he need to make the need 80 liters of 30% acid solution.
Let x be the number of liters of the 20% solution that Gabe needs and y be the number of liters of the 60% solution that he needs.
To make 80 liters of a 30% solution, the amount of acid in the mixture must be:
0.3(80) = 24 liters
We know that we need a total of 80 liters of solution, so:
x + y = 80
We also know that the amount of acid in the 20% solution is:
0.2x
Similarly, the amount of acid in the 60% solution is:
0.6y
The total amount of acid in the final mixture is 24 liters, so:
0.2x + 0.6y = 24
Now we have two equations:
x + y = 80
0.2x + 0.6y = 24
We can use algebra to solve for x and y. Here's one way to do it:
1. Multiply the first equation by 0.2 to get:
0.2x + 0.2y = 16
2. Subtract the above equation from the second equation to eliminate x:
0.6y - 0.2x - 0.2y = 24 - 16
0.4y = 8
y = 20
3. Substitute y = 20 into the first equation to solve for x:
x + 20 = 80
x = 60
So Gabe needs 60 liters of the 20% solution and 20 liters of the 60% solution to make 80 liters of a 30% solution.
To make 80 liters of a 30% solution, the amount of acid in the mixture must be:
0.3(80) = 24 liters
We know that we need a total of 80 liters of solution, so:
x + y = 80
We also know that the amount of acid in the 20% solution is:
0.2x
Similarly, the amount of acid in the 60% solution is:
0.6y
The total amount of acid in the final mixture is 24 liters, so:
0.2x + 0.6y = 24
Now we have two equations:
x + y = 80
0.2x + 0.6y = 24
We can use algebra to solve for x and y. Here's one way to do it:
1. Multiply the first equation by 0.2 to get:
0.2x + 0.2y = 16
2. Subtract the above equation from the second equation to eliminate x:
0.6y - 0.2x - 0.2y = 24 - 16
0.4y = 8
y = 20
3. Substitute y = 20 into the first equation to solve for x:
x + 20 = 80
x = 60
So Gabe needs 60 liters of the 20% solution and 20 liters of the 60% solution to make 80 liters of a 30% solution.