To determine which table might represent Ava's line, we need to find the slope based on her expression \(5 - 14 - 2\).
Let's simplify that expression:
- \(5 - 14 = -9\)
- \(-9 - 2 = -11\)
Therefore, the slope of the line Ava is looking for is \(-11\).
Now, we'll check the slope between the points in each table. The slope between two points \((x_1, y_1)\) and \((x_2, y_2)\) is calculated using the formula:
\[ \text{slope} = \frac{y_2 - y_1}{x_2 - x_1} \]
Table 1
\[ \begin{align*} (x, y) & : (2, 1) \ (x, y) & : (4, 5) \end{align*} \] Calculating the slope: \[ \text{slope} = \frac{5 - 1}{4 - 2} = \frac{4}{2} = 2 \]
Table 2
\[ \begin{align*} (x, y) & : (5, 4) \ (x, y) & : (1, 2) \end{align*} \] Calculating the slope: \[ \text{slope} = \frac{2 - 4}{1 - 5} = \frac{-2}{-4} = \frac{1}{2} \]
Table 3
\[ \begin{align*} (x, y) & : (2, 5) \ (x, y) & : (4, 1) \end{align*} \] Calculating the slope: \[ \text{slope} = \frac{1 - 5}{4 - 2} = \frac{-4}{2} = -2 \]
Table 4
\[ \begin{align*} (x, y) & : (4, -5) \ (x, y) & : (2, -1) \end{align*} \] Calculating the slope: \[ \text{slope} = \frac{-1 + 5}{2 - 4} = \frac{4}{-2} = -2 \]
After evaluating the slopes from all the tables, none match the calculated slope of \(-11\). It suggests that there might be some confusion regarding the points that would lead to a slope of \(-11\).
To find pairs of points that yield a slope of \(-11\), you can work backward.
Using the slope formula to find new pairs:
From \(y - y_1 = m(x - x_1)\) where \(m = -11\):
Let’s say we have a point \((x_1, y_1)\) and want to find a point with \(x_2\):
\[ y_2 = y_1 - 11(x_2 - x_1) \]
You can substitute different values for \(x_2\) and for points that Ava may have chosen to get a slope of \(-11\).
Thus, based on the calculations, none of the provided tables represent Ava's line correctly with the slope of \(-11\).