speed on first leg ---- x mph
speed on return trip -- x+21 mph
distance on first leg = 8x
distance for return leg = 5(x+21)
but the distances are equal, so
8x = 5(x+21)
8x = 5x + 105
3x=105
x = 35
distance = 8(35) = 280 miles
Austin drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took
8 hours. When Austin drove home, there was no traffic and the trip only took
5 hours. If his average rate was
21 miles per hour faster on the trip home, how far away does Austin live from the mountains?
Do not do any rounding.
2 answers
Just realized I did this same question a few weeks back
http://www.jiskha.com/display.cgi?id=1443062344
http://www.jiskha.com/display.cgi?id=1443062344
1 answer