The first rxn is reduction. Au went from +3 to 0 so higher to lower number (became more -ve)
Na is oxidized. went form 0 to +3
Au^3+ + 3e^- ---> Au
Is this oxidation or reduction?
Which reactant has been oxidized?
Au3+ (aq)+ 3Na(s)--->3Na^+(aq)+Au(s)
2.Which reactant has been reduced
3.What is the reducing agent?
4.what is the oxidizing agent?
I am having a hard time understanding how to do these. If you could be so kind as to help me I would love it! Thanks heads up!!!
5 answers
Is the Na one the anwser to number 1 and (went from 0 to +3) number 3? Whats number 4? Thanks
What is your charge for Au? There has to be a positive and negative- check your equations- that answers then may not apply.
Positive and negative- in the sense things should cancel and charges should inc. and dec.
#4. Ths oxidizing agent is the substance reduced. The reducing agent is the substance oxidized.
Na is the reducing agent and it is oxidized.
Au^3+ is the oxidizing agent and it is reduced.
Na is the reducing agent and it is oxidized.
Au^3+ is the oxidizing agent and it is reduced.
2 answers