Atom Ant is traveling with an initial velocity of 20.0 cm/s. He begins to accelerate at a rate of 8.00 cm/s2 for 5.00 s. What is his total displacement in the 5.00 second interval? What is his displacement in the last second?

Answer 1

d= vi*t+1/2 a t^2
vi is given, a is given, in the last second
find d for t=5 seconds, then t=4 seconds, the difference is the displacment in the last second.