Atlanta list the ages of all of the family members who live in her house what is the mean absolute deviation of their ages age 9 age 13 age 43 age 55 a28 b38 C 76 d19

Answer 1

To find the mean absolute deviation (MAD) of the ages, follow these steps:

1. List the ages: 9, 13, 43, 55, 28, 38.

2. Calculate the mean: \[ \text{Mean} = \frac{(9 + 13 + 43 + 55 + 28 + 38)}{6} = \frac{186}{6} = 31 \]

3. Calculate the absolute deviations from the mean: \[ |9 - 31| = 22 \] \[ |13 - 31| = 18 \] \[ |43 - 31| = 12 \] \[ |55 - 31| = 24 \] \[ |28 - 31| = 3 \] \[ |38 - 31| = 7 \]

4. List the absolute deviations: 22, 18, 12, 24, 3, 7.

5. Calculate the mean of the absolute deviations: \[ \text{MAD} = \frac{(22 + 18 + 12 + 24 + 3 + 7)}{6} = \frac{86}{6} \approx 14.33 \]

So the mean absolute deviation of the ages is approximately 14.33.

If you're interested in the options provided (A 28, B 38, C 76, D 19), none of these match the calculated mean absolute deviation.

Please verify your options or the question requirements.