find the equation of the straight line between the two given points in the usual way, then
in that equation, let y = 0 and solve for x
at what value of x does the perpendicular bisector of the line segment with endpoints (-2,6) and (5,-4) cross the x-axis?
2 answers
Given:(-2,6),(5,-4). Mid-point:
Xo=(-2+5)/2=3/2, Yo=(6-4)/2=1,M(3/2,1),
Slope=(-4-6)/(5+2)=-7/10, Slope of
perpendicular bisector=7/10, Y=mX+b,
1=7/10*(3/2)+b, b=-1/20,Y=7/10X-1/20,
Y=7/10X-1/20=0,X=1/14=X-Intercept.
Xo=(-2+5)/2=3/2, Yo=(6-4)/2=1,M(3/2,1),
Slope=(-4-6)/(5+2)=-7/10, Slope of
perpendicular bisector=7/10, Y=mX+b,
1=7/10*(3/2)+b, b=-1/20,Y=7/10X-1/20,
Y=7/10X-1/20=0,X=1/14=X-Intercept.