Sorry the equation is wrong it should be
W(t)=5 (t-10(t-20)+4500
at what time does this equation reaches 10000? show steps. thanks
w(t)=(t-10)(t-20)+4500
5 answers
set 5(t-10)(t-20)+4500 = 10000
5(t-10)(t-20) = 5500
(t-10)(t-20) = 1100
t^2 - 30t + 200 = 1100
t^2 - 30 t = 900
I will complete the square..
t^2 - 30t + 225 = 1125
(t-15)^2 = 1125
t - 15 = ±√1125 = ±15√5
t = 15 ± 15√5 , but more than likely t > 0
so t = 15 + 15√5 or appr 48.541
5(t-10)(t-20) = 5500
(t-10)(t-20) = 1100
t^2 - 30t + 200 = 1100
t^2 - 30 t = 900
I will complete the square..
t^2 - 30t + 225 = 1125
(t-15)^2 = 1125
t - 15 = ±√1125 = ±15√5
t = 15 ± 15√5 , but more than likely t > 0
so t = 15 + 15√5 or appr 48.541
Calculate 5*(t-10)(t-20)=5500
umhh,
We don't 'calculate' 5*(t-10)(t-20)=5500
we "solve" 5*(t-10)(t-20)=5500
and I believe I just did that for you.
We don't 'calculate' 5*(t-10)(t-20)=5500
we "solve" 5*(t-10)(t-20)=5500
and I believe I just did that for you.
Thanks Reiny :D