Asked by Marty

At what temperatures can 40mL of water dissolve the follownig quantities of potassium nitrate?
(a) 35.0g (b) 20.0g

can anyone start me off with a formula or a hint?
Answered by DrBob222
Don't you have somewhere the solubility of KNO3 in water at various temperatures?
Answered by Marty
Would a solubility curve help?
Answered by DrBob222
Yes. What is on the x axis and what is on the y axis?
Answered by Marty
on the x axis is temperature (degrees celsius) and on the y axis is solubility (g/100g H20).
Is there any mathematical way to figure this out instead of using the solubility curve.
Answered by DrBob222
Yes. Generally the question is how much water will it take to dissolve so much KNO3 at a particular T (and you are given the solubility at those Ts); however, this problem isn't that. You will need a table of solubility vs T or a curve.
Answered by DrBob222
You want to dissolve 20 g in 40 mL water. We will assume the density of water is 1.00 g/mL; therefore, 40 mL = 40 g water.
How much is that per 100?
20 g x (100/40) = 50 g KNO3
Now look on your curve and read the T that dissolves 50 g KNO3.
Same kind of procedure for 35 g KNO3.
Answered by Marty
what are the units of 100 and 40?
Answered by DrBob222
grams.
20 g KNO3 is what you want to dissolve.
Your curve shows solubility per 100 g H2O. So we convert 20 g KNO3/40 g H2O to xx g KNO3/100 g H2O.

20 g KNO3 x (100 g H2O/40 g H2O) = 50 g KNO3/100 g H2O. And that is how the solubility curve is plotted. So on the x axis find 50 g KNO3, move straight up to the curve, at the intersection with the curve, move horizontally to the left and read T on the Y axis.
Answered by gill
gave answer my question
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