At what projection angle will the range of a projectile equal to 3 times its maximum height?

Answer 1

The range is 2(V^2/g)*sinA cosA.

The maximum height is (V^2/2g) sin^2A

If range = 3 x (max height),
2sinA cosA = (3/2) sin^2A, and
4/3 = tan A

A = 53.1 degrees

Answer 2

thanks so much