Question

At what point on the curve
x = 3t^2 + 6, y = t^3 − 3 does the tangent line have slope 1/2?

(x, y) =

Answer 1

well, at any point (x,y) the slope is
dy/dx = (dy/dt) / (dx/dt) = (3t^2)/(6t) = t/2

sure looks like t=1, so the point is (9,-2)

Answer 2

thank you so much :) i wanted to make sure that my answer was right

Answer 3

should have posted <u>your</u> work so that we could check it ...