At what point does the graph of the parametric equations y=3-2t, y=-2+5t intersect the graph of the parametric equations x = -1+3s,y=5-9s. The answer is the point of intersection (x,y).

Question

Please help! I am really confused!

Answer 1

I am a bit confused myself, unless you have a typo.
I will assume you meant your first set to be
x = 3-2t, y = -2 + 5t

so -1+ 3s = 3 - 2t ---> 2t + 3s = 4 **
and
-2 + 5t = 5 - 9s ---> 5t + 9s = 7 ***

3 times ** ---> 6t + 9s = 12
subtract ***
t = 5
back in **
10 + 3s = 4
3s = -6
s = -2

then x = 3 -2t = 3 -10 = -7
y = -2+5t = -2 + 25 = 23

(x,y) = (-7, 23)

OR

If you meant it the way you typed it ....
from the first, since they are both equal to y
-2+5t = 3-2t
7t = 5
t = 5/7

-2 + 5t = 5 - 9s ---> 5t + 9s = 7
sub in t = 5/7
25/7 + 9s = 7
9s = 24/7
s = 8/21


since x = -1+3s
x = -1 + 8/7 = 1/7
y = 3-2t = 3-10/7 = 11/7

point would be ( 1/7, 11/7)

Answer 2

Sorry it was a typo it was the first one thanks a lot!!!