At what does the curve f(x)=x/x-2 have a tangent with a slope of -1/2 ?

Answer 1

f'(x) = -2/(x-2)^2
so, we need
-2/(x-2)^2 = -2
x = 1 or 3

Answer 2

Would you be able to determine the point?

Answer 3

well, duh.
f(1) = 1/(1-2) = -1
so the point is (1,-1)

do f(3) in like wise.

Answer 4

Thanks for the help!!