To find the maximum number of families that can attend the picnic with the hot dogs and hamburgers divided equally, we need to determine how many families can equally share 480 hot dogs and 320 hamburgers.
First, we calculate the greatest common divisor (GCD) of 480 and 320 to find the maximum number of families that can share both types of food equally.
Finding the GCD:
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Prime Factorization:
- For 480: \[ 480 = 2^5 \times 3^1 \times 5^1 \]
- For 320: \[ 320 = 2^6 \times 5^1 \]
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Identifying common factors:
- The common prime factors in both 480 and 320 are \(2\) and \(5\).
- The minimum power of \(2\) in both is \(2^5\), and for \(5\) it's \(5^1\).
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Calculating the GCD: \[ \text{GCD} = 2^5 \times 5^1 = 32 \times 5 = 160 \]
Now that we have 160 as the GCD, this indicates that the maximum number of families that can equally receive hot dogs and hamburgers is:
\[ \text{Maximum families} = \frac{480 \text{ hot dogs}}{160} = 3 \] \[ \text{Maximum families} = \frac{320 \text{ hamburgers}}{160} = 2 \]
However, since the families can only be equal in the least common distribution, we consider the total items divided against the GCD. Since the GCD of hot dogs and hamburgers is 160, that will set the allocation amount per family to ensure both items can be evenly divided.
Thus, the maximum number of families that can attend and receive an equal share of hot dogs and hamburgers is:
\[ 80 \text{ families} , \text{(both hot dogs and hamburgers can be divided into 80 portions)} \]
Therefore, the correct answer is 80 families.