At the top of the serve, the racket has an angular speed of 23.7 rad/s. If the distance between the top of the racket and the shoulder is 1.39 m, find the magnitude of the total acceleration of the top of the racket.

Answer 1

assuming the racket velocity is constant, and not changing, then the centripetal acceleration downward is 23.7^2 * 1.39 m/sec^2