To calculate the future value of the account at the child's twenty-first birthday, we'll use the formula for compound interest:
\[ A = P \left(1 + \frac{r}{n}\right)^{nt} \]
Where:
- \( A \) = the future value of the investment/loan, including interest
- \( P \) = the principal investment amount (the initial deposit or loan amount) = $1000
- \( r \) = the annual interest rate (decimal) = 2% = 0.02
- \( n \) = the number of times that interest is compounded per year = 12 (monthly)
- \( t \) = the number of years the money is invested or borrowed for = 21 years
Now let’s plug in the values into the formula:
\[ A = 1000 \left(1 + \frac{0.02}{12}\right)^{12 \times 21} \]
Calculating \( \frac{0.02}{12} \):
\[ \frac{0.02}{12} = 0.00166667 \]
Now substitute this back into the formula:
\[ A = 1000 \left(1 + 0.00166667\right)^{12 \times 21} \]
Calculating \( 12 \times 21 \):
\[ 12 \times 21 = 252 \]
So now we have:
\[ A = 1000 \left(1.00166667\right)^{252} \]
Next, we can calculate \( \left(1.00166667\right)^{252} \):
Using a calculator:
\[ 1.00166667^{252} \approx 1.490665 \]
Finally, we multiply this by the principal amount:
\[ A \approx 1000 \times 1.490665 \approx 1490.67 \]
Thus, the value of the account at the child's twenty-first birthday will be approximately $1490.67.