To determine which solutions are reasonable given that hot dogs cost $4 each and bottled water costs $2 each, and that less than $12 worth of hot dogs and water were sold, we can set up the inequality:
\[ 4x + 2y < 12 \]
where \(x\) is the number of hot dogs sold and \(y\) is the number of bottles of water sold. We will evaluate each of the provided pairs \((x, y)\) to see if they satisfy this inequality.
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(–1, 5): \[ 4(-1) + 2(5) = -4 + 10 = 6 \quad \text{(valid, since } 6 < 12\text{)} \]
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(0, 6): \[ 4(0) + 2(6) = 0 + 12 = 12 \quad \text{(not valid, since } 12 \not< 12\text{)} \]
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(2, 1): \[ 4(2) + 2(1) = 8 + 2 = 10 \quad \text{(valid, since } 10 < 12\text{)} \]
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(1, 1.5): \[ 4(1) + 2(1.5) = 4 + 3 = 7 \quad \text{(valid, since } 7 < 12\text{)} \]
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(1, 3): \[ 4(1) + 2(3) = 4 + 6 = 10 \quad \text{(valid, since } 10 < 12\text{)} \]
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(2, 2): \[ 4(2) + 2(2) = 8 + 4 = 12 \quad \text{(not valid, since } 12 \not< 12\text{)} \]
Now, we can summarize the results:
- Valid solutions: (–1, 5), (2, 1), (1, 1.5), (1, 3)
- Invalid solutions: (0, 6), (2, 2)
Reasonable solutions for the situation are:
- (–1, 5)
- (2, 1)
- (1, 1.5)
- (1, 3)