At the normal boiling point of toluene,Δ Hvap=33.2 kJ/mol and ΔSvap= 86.5J/mol•K. What is the normal boiling point of toluene?

Answer 1

dG = dH-TdS
At equilibrium (boiling is an equilibrium process), dG = 0. Substitute dH and dS and solve for Tb.

Answer 2

A little lost but I'm getting 384...