At the heighest point on earth, the distance to the center of the earth is approximately equal to 1.0014 times the radius of the earth. What would be in N/kg the magnitude of the gravitational field (g) due to the earth at that position? Assume 9.8 N/kg for g at the surface of the earth.
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g=GM/R2 also g'=GM/r2 gR2=GM=g'2 9.8R2=g'(1.0014R)2 g'=9.77N/kg
1 answer