At the end of a race a runner decelerates from a velocity of 7.00 m/s at a rate of 0.300 m/s2.

Answer 1

Two fixed charges 1.07mC and -3.28mC are 61.8 cm apart. Where the third charge may be placed so that no net force acts on it?

Answer 2

x=vt+1/2at^2
x=7(15)-1/2(4)(15^2)
x=71.25