Fb = M*g = 13 * 9.8 = 127.4 N.
Fp = 127.4*sin 0 = 0. = Force parallel to the floor.
Fn = 127.4 - 86.4*sin64. = Normal force.
Fk = u*Fn = Force of kinetic friction.
a = (F*Cos64-Fp-Fk)/M.
At the beginning of a new school term, a student moves a box of books by attaching a rope to the box and pulling with a force of F=86.4 N at an angle of 64 degree.
The acceleration of gravity is 9.8 m/s^2.
The box of books has a mass of 13 kg and the coefficient of kinetic friction between the bottom of the box and the floor is 0.31.
What is the acceleration of the box?
Answer in units of m/s^2
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