one way. figure the percent lead in PbS, and the percent in PbO, then add the mass of lead in each.
another way.
2PbO+PbS>>3Pb + SO2
calculate the moles of PbO in 890kg. then the moles of pb is 3/2 times that. Reconvert that to mass.
At temperatures above 930 ∘C, PbO reduces PbS to form metallic lead (Pb). The byproduct of the reaction is SO2. Calculate the amount of lead produced (in kg) when a reactor is charged with 593.0 kg of PbS and 890 kg of PbO.
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