at some temperature, Keq=33 for the reaction H2 + I2 - 2HI. If initially, [H2]= .0600 M and [I2]= .0300 M, what are all three equilibrium concentrations?

Question

at some temperature, Keq=33 for the reaction H2 + I2 -> 2HI. If initially, [H2]= .0600 M and [I2]= .0300 M, what are all three equilibrium concentrations?

bobpursley · Answer

keq=(2x)^2/ (.06-x)(.03-x)=33 4x^2=33(.0018+x^2-.09x) -29x^2+.09&33 x- .0018*33=0 ok,use the quadratic eqauation, solve for x. 2x is the conc of HI .06-x is the conc of H2 .03-x is the conc of I2