At some instant, a particle traveling in a horizontal circular path of radius 7.50 m has a total acceleration with a magnitude of 16.0 m/s^2 and a constant tangential acceleration of 12.0 m/s^2. Determine the speed of the particle at this instant and (1/8) revolution later.
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Hey sorry! My browser is doing weird things and didn't allow me to see this had already posted! Didn't mean to repeat.
OK so figured it out, solve for the centripetal acceleration and then velocity. Use that velocity and use the third circular motion kinematic equation, to solve for v final.
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