At Pizza Palace, the price of a pizza is a quadratic function of the diameter. The prices of three pizzas at Pizza Palace are shown in the following table: Diameter of Pizza (inches) Price of Pizza (dollars) 12" $15.80 16" $22.20 20" $35.00 Question Use the three points from the table to write the equation of the parabola that passes through the points.

1 answer

We have three points corresponding to the given diameters and prices of pizzas at Pizza Palace:

  1. \( (12, 15.80) \)
  2. \( (16, 22.20) \)
  3. \( (20, 35.00) \)

We can express the price \( P \) as a quadratic function of the diameter \( d \) in the form:

\[ P(d) = ad^2 + bd + c \]

where \( a \), \( b \), and \( c \) are coefficients we need to determine.

Using the three points, we can set up a system of equations:

  1. From \( (12, 15.80) \): \[ a(12^2) + b(12) + c = 15.80 \] \[ 144a + 12b + c = 15.80 \quad \text{(Equation 1)} \]

  2. From \( (16, 22.20) \): \[ a(16^2) + b(16) + c = 22.20 \] \[ 256a + 16b + c = 22.20 \quad \text{(Equation 2)} \]

  3. From \( (20, 35.00) \): \[ a(20^2) + b(20) + c = 35.00 \] \[ 400a + 20b + c = 35.00 \quad \text{(Equation 3)} \]

Now we will organize our equations:

  1. \( 144a + 12b + c = 15.80 \)
  2. \( 256a + 16b + c = 22.20 \)
  3. \( 400a + 20b + c = 35.00 \)

Next, we will eliminate \( c \) from these equations. We can do this by subtracting Equation 1 from Equation 2, and Equation 2 from Equation 3.

Subtract Equation 1 from Equation 2:

\[ (256a + 16b + c) - (144a + 12b + c) = 22.20 - 15.80 \] \[ (256 - 144)a + (16 - 12)b = 6.40 \] \[ 112a + 4b = 6.40 \quad \text{(Equation 4)} \]

Subtract Equation 2 from Equation 3:

\[ (400a + 20b + c) - (256a + 16b + c) = 35.00 - 22.20 \] \[ (400 - 256)a + (20 - 16)b = 12.80 \] \[ 144a + 4b = 12.80 \quad \text{(Equation 5)} \]

Now we have a new system of two equations with two unknowns:

  1. \( 112a + 4b = 6.40 \)
  2. \( 144a + 4b = 12.80 \)

We can now eliminate \( b \) by subtracting Equation 4 from Equation 5:

\[ (144a + 4b) - (112a + 4b) = 12.80 - 6.40 \] \[ 32a = 6.40 \] \[ a = \frac{6.40}{32} = 0.20 \]

Now we can substitute \( a = 0.20 \) back into Equation 4 to find \( b \):

\[ 112(0.20) + 4b = 6.40 \] \[ 22.40 + 4b = 6.40 \] \[ 4b = 6.40 - 22.40 \] \[ 4b = -16 \] \[ b = -4 \]

Now that we have \( a \) and \( b \), we can find \( c \) by substituting \( a \) and \( b \) back into one of the original equations; we can use Equation 1:

\[ 144(0.20) + 12(-4) + c = 15.80 \] \[ 28.8 - 48 + c = 15.80 \] \[ c = 15.80 - 28.8 + 48 \] \[ c = 15.80 - 28.8 + 48 = 35.00 \]

Thus, we have found:

  • \( a = 0.20 \)
  • \( b = -4 \)
  • \( c = -35.00 \)

Putting it all together, the equation of the parabola that models the price of pizza as a function of its diameter is:

\[ P(d) = 0.20d^2 - 4d + 35.00 \]