At one end of the Venturi Tube the pressure and speed of flowing water is 21 kPa and 0.05m/s respectively. At another point the pressure is 5 kPa. Find the speed of the water at the second point. Answer in m/s

Answer 1

p1+1/2 dV1^2=p2+cV2^2 d=densitywater
23k+1/2 *1E3*.0025=5k+1/2*1E3*V2^2

V2^2=(23E3 +500*.0025-5000)/500
= 36

V2=6m/s

check my math.

Answer 2

The math was right, but 23k should be 2k Pa

Answer 3

23 should be 21

Answer 4

So, the answer is 0.0351240737 m/s