Asked by jamie
                At her wedding, Jennifer lines up all the single females in a straight line away from her in preperation for the tossing of the bridal bouquet. She stands Kelly at 1.0 m, Kendra at 1.5 m, Mary at 2.0 m, Kristen at 2.5 m, and Lauren at 3.0 m. Jennifer turns around and tosses the bouquet behind her with a speed of 3.9 m/s, at an angle of 50 degrees and it is caught at the same height 0.60 seconds later. Who catches the bridal bouquet and who might have caught it if she had thrown it more slowly?
            
            
        Answers
                    Answered by
            bobpursley
            
    Air resistance?
Assuming (I love that word) no air resistance, then the vertical component of velocity is 3.9sin50. When it gets back to the same altitude as it was launched,
0=0+3.9sin50-4.9t solve for t.
Then, how far did it travel?
d= 3.9cos50 * t
    
Assuming (I love that word) no air resistance, then the vertical component of velocity is 3.9sin50. When it gets back to the same altitude as it was launched,
0=0+3.9sin50-4.9t solve for t.
Then, how far did it travel?
d= 3.9cos50 * t
                    Answered by
            Anonymous
            
    1.5
    
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